Physicshard · Past Paper

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. A force F is applied at one end of the rope. The work done by the rope on the block is:

AFs
B[M/(M+m)]Fs
C[m/(M+m)]Fs
DZero

✓ Correct Answer: B — [M/(M+m)]Fs

Acceleration a = F/(M+m). Tension on block = Ma = MF/(M+m). Work = Tension * s = [MF/(M+m)]s.

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