Physicshard · Past Paper
A ball of mass m is dropped from height h. It rebounds to height h1. The energy lost is:
Amgh
Bmgh1
Cmg(h - h1)
Dmg(h + h1)
✓ Correct Answer: C — mg(h - h1)
Energy loss = Initial PE - Final PE = mgh - mgh1 = mg(h - h1).
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