Physicshard · Past Paper
What is the magnitude of acceleration for an object moving with velocity v = 5t^2 + 2t at t = 1s?
A7 m/s^2
B10 m/s^2
C12 m/s^2
D5 m/s^2
✓ Correct Answer: C — 12 m/s^2
a = dv/dt = 10t + 2. At t=1, a = 10(1) + 2 = 12 m/s^2.
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