Physicshard · Past Paper

What is the displacement of a point on the rim of a wheel of radius R when the wheel rolls forward half a revolution?

A2R
Bpi*R
CR*sqrt(pi^2 + 4)
DR*sqrt(pi^2 + 1)

✓ Correct Answer: CR*sqrt(pi^2 + 4)

Horizontal distance = pi*R, vertical distance = 2R. Resultant displacement = sqrt((pi*R)^2 + (2R)^2) = R*sqrt(pi^2 + 4).

Share this question

More from Physics