Physicshard · Past Paper
If the velocity of a particle is given by v = At + Bt^2, where A and B are constants, then the distance traveled by it between 1s and 2s is:
A3A/2 + 7B/3
BA/2 + B/3
C3A/2 + B/3
DA + B
✓ Correct Answer: A — 3A/2 + 7B/3
Distance = integral from 1 to 2 of (At + Bt^2)dt = [At^2/2 + Bt^3/3] from 1 to 2 = (2A + 8B/3) - (A/2 + B/3) = 1.5A + 7/3B.
Share this question
More from Physics
- The center of the reflecting surface of a spherical mirror is called:
- If a body is moving in a circle with constant speed, the work done by centripetal force is:
- Work done by a force can be calculated as the area under which graph?
- The rate of flow of electric charge is called:
- A stone is dropped into a well 44.1m deep. The sound of splash is heard 3.13s later. The velocity of sound is: