Physicsmedium · Past Paper
If distance s = 2t + 5t^2, then the initial velocity is:
A2 m/s
B5 m/s
C10 m/s
D0 m/s
✓ Correct Answer: A — 2 m/s
v = ds/dt = 2 + 10t. At t=0 (initial), v = 2 m/s.
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✓ Correct Answer: A — 2 m/s
v = ds/dt = 2 + 10t. At t=0 (initial), v = 2 m/s.
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