Physicsmedium · Past Paper
An object covers 1/4th of a circular path of radius r. The magnitude of its displacement is:
Aπr/2
Br√2
Cr
D2r
✓ Correct Answer: B — r√2
The displacement is the chord length. Using Pythagoras theorem, d = √(r^2 + r^2) = r√2.
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