Physicsmedium · Past Paper
An object covers 1/4th of a circular path of radius r. The magnitude of its displacement is:
Aπr/2
Br√2
Cr
D2r
✓ Correct Answer: B — r√2
The displacement is the chord length. Using Pythagoras theorem, d = √(r^2 + r^2) = r√2.
Share this question
More from Physics
- A force of 5 N acts on a body and the body moves 10 m at an angle of 60 degrees to the direction of force. The work done is:
- When the speed of a moving body is doubled, its momentum is:
- The unit of refractive index is:
- A solenoid of length 0.5m has 500 turns. If 2A current flows, calculate the magnetic field strength (take μ₀ = 4π x 10^-7 T m/A).
- If the distance is doubled for a constant force, the work done is: