Physicshard · Past Paper

A particle moves along a straight line. After 't' seconds, the distance 's' (in meters) from the starting point is given by s = 8t + 3t^2. Find the velocity at t = 2s.

A14 m/s
B20 m/s
C28 m/s
D32 m/s

✓ Correct Answer: B20 m/s

v = ds/dt = 8 + 6t. At t=2, v = 8 + 6(2) = 20 m/s.

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