Physicshard · Past Paper
A particle has an initial velocity of 3i + 4j and an acceleration of 0.4i + 0.3j. Its speed after 10s is:
A7 units
B7*sqrt(2) units
C10 units
D5 units
✓ Correct Answer: B — 7*sqrt(2) units
v = u + at = (3+4)i + (4+3)j = 7i + 7j. Speed = sqrt(7^2 + 7^2) = 7*sqrt(2).
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