Physicshard · Past Paper
A car accelerates from rest at a constant rate 'α' for some time, after which it decelerates at a constant rate 'β' and comes to rest. If the total time elapsed is 'T', the maximum velocity acquired by the car is:
A(αβT) / (α+β)
B(α+β)T / αβ
C(α^2 + β^2)T
DαβT
✓ Correct Answer: A — (αβT) / (α+β)
v_max = a1*t1 and v_max = a2*t2. With t1+t2=T, solving gives v_max = (αβT)/(α+β).
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