Physicshard · Past Paper
A body is moving with constant acceleration. If the distances traveled in 'p'th and 'q'th seconds are 'x' and 'y' respectively, then the acceleration is:
A(x-y) / (p-q)
B(x+y) / (p+q)
C(p-q) / (x-y)
Dxy / (p-q)
✓ Correct Answer: A — (x-y) / (p-q)
Sp = u + a/2(2p-1), Sq = u + a/2(2q-1). x - y = a/2(2p-2q) = a(p-q). So a = (x-y)/(p-q).
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