Physicshard · Past Paper
A body is dropped from a height H. The time taken to cover the second half of the height is:
A√(2H/g)
B√(H/g)
C√(2H/g) * (1 - 1/√2)
D√(H/g) / 2
✓ Correct Answer: C — √(2H/g) * (1 - 1/√2)
Time for H is T=√(2H/g). Time for H/2 is t=√(H/g). Difference is the time for the second half.
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