Physicshard · Past Paper
A metal cube of side 10 cm and density 8000 kg/m³ is suspended in water. The upthrust is:
A80 N
B10 N
C1 N
D8 N
✓ Correct Answer: B — 10 N
Volume = (0.1)³ = 0.001 m³. Upthrust = Vdg = 0.001 * 1000 * 10 = 10 N.
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