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A hydraulic lift has pistons of area 2 m² and 10 m². If 100 N is applied to the small piston, what is the force on the large one?

A500 N
B20 N
C100 N
D1000 N

✓ Correct Answer: A500 N

By Pascal's law, P1 = P2. So, F1/A1 = F2/A2 => 100/2 = F2/10 => F2 = 500 N.

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