Physicshard · Past Paper
A cell of EMF 2V and internal resistance 0.5 Ohm is connected to an external resistance of 9.5 Ohms. What is the terminal potential difference?
A2.0 V
B1.9 V
C1.5 V
D0.1 V
✓ Correct Answer: B — 1.9 V
I = E/(R+r) = 2/(9.5+0.5) = 0.2A. Terminal V = E - Ir = 2 - (0.2*0.5) = 1.9V.
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