In the reaction $I_2 + 2S_2O_3^{2-} \rightarrow 2I^- + ... – Chemistry

Chemistryhard · Past Paper

In the reaction $I_2 + 2S_2O_3^{2-} \rightarrow 2I^- + S_4O_6^{2-}$, iodine is acting as a/an:

AReducing agent

BOxidizing agent

CCatalyst

DAcid

✓ Correct Answer: B — Oxidizing agent

Iodine (I2) gains electrons to become I- (reduction), so it acts as an oxidizing agent.

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