Chemistryhard · Past Paper
How many molecules of water are present in 180g of water?
A6.022 x 10^23
B6.022 x 10^24
C1.8 x 10^23
D3.011 x 10^23
✓ Correct Answer: B — 6.022 x 10^24
180g = 10 moles. 10 * Avogadro's number = 6.022 x 10^24.
Share this question