Chemistryhard · Past Paper

How many molecules of water are present in 180g of water?

A6.022 x 10^23
B6.022 x 10^24
C1.8 x 10^23
D3.011 x 10^23

✓ Correct Answer: B6.022 x 10^24

180g = 10 moles. 10 * Avogadro's number = 6.022 x 10^24.

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