Biologyhard · Past Paper

In a dihybrid cross ($RRYY \times rryy$), what is the probability of getting an $RrYy$ genotype in the F2 generation?

A1/16
B2/16
C4/16
D9/16

✓ Correct Answer: C4/16

In the $9:3:3:1$ dihybrid cross, the double heterozygote $RrYy$ occurs in 4 out of 16 boxes of the Punnett square.

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