Trigonometryhard · Past Paper

What is the value of 1 / (1 + sin²θ) + 1 / (1 + cosec²θ)?

A1
B2
Csin²θ
Dcosec²θ

✓ Correct Answer: A1

1/(1+sin²) + 1/(1 + 1/sin²) = 1/(1+sin²) + sin²/(sin²+1) = (1+sin²)/(1+sin²) = 1.

Share this question

More from Trigonometry