Trigonometrymedium · Past Paper
Simplify: (cosec²θ - 1) / cosec²θ
Asin²θ
Bcos²θ
Ctan²θ
Dcot²θ
✓ Correct Answer: B — cos²θ
(cot²θ) / (cosec²θ) = (cos²/sin²) / (1/sin²) = cos²θ.
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✓ Correct Answer: B — cos²θ
(cot²θ) / (cosec²θ) = (cos²/sin²) / (1/sin²) = cos²θ.
Share this question