Trigonometrymedium · Past Paper
In a right triangle, if sin theta = a/b, then cos theta is:
Ab / sqrt(b^2 - a^2)
Bsqrt(b^2 - a^2) / b
Csqrt(b^2 + a^2) / b
Da / sqrt(b^2 - a^2)
✓ Correct Answer: B — sqrt(b^2 - a^2) / b
base = sqrt(hypotenuse^2 - perpendicular^2) = sqrt(b^2 - a^2). cos = base/hypotenuse = sqrt(b^2 - a^2)/b.
Share this question