Trigonometryhard · Past Paper
If sin θ = 1/3, find the value of (2 cot²θ + 2).
A6
B9
C18
D12
✓ Correct Answer: C — 18
2(cot²θ + 1) = 2 cosec²θ = 2 * (1/sin)² = 2 * 9 = 18.
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✓ Correct Answer: C — 18
2(cot²θ + 1) = 2 cosec²θ = 2 * (1/sin)² = 2 * 9 = 18.
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