Trigonometryhard · Past Paper
If 7 sin²θ + 3 cos²θ = 4, then tan θ is:
A√3
B1/√3
C1
D0
✓ Correct Answer: B — 1/√3
4 sin²θ + 3(sin²θ + cos²θ) = 4 => 4 sin²θ + 3 = 4 => sin²θ = 1/4 => sin θ = 1/2. θ=30. tan 30 = 1/√3.
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✓ Correct Answer: B — 1/√3
4 sin²θ + 3(sin²θ + cos²θ) = 4 => 4 sin²θ + 3 = 4 => sin²θ = 1/4 => sin θ = 1/2. θ=30. tan 30 = 1/√3.
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