Trigonometrymedium · Past Paper

Simplify: tan θ + cot θ.

Asec θ cosec θ
B2 / sin 2θ
C1 / (sin θ cos θ)
DAll of the above

✓ Correct Answer: DAll of the above

tan + cot = sin/cos + cos/sin = (sin² + cos²) / (sin cos) = 1 / (sin cos) = sec cosec = 2/sin 2θ.

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