Trigonometrymedium · Past Paper
In a triangle ABC, if A + B + C = 180°, then sin(A + B) is equal to:
Asin C
B-sin C
Ccos C
D-cos C
✓ Correct Answer: A — sin C
sin(A+B) = sin(180 - C) = sin C, as sine is positive in the second quadrant.
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