Trigonometryhard · Past Paper
The angle of elevation of the top of a tower from a point A due south is 30° and from B due east is 45°. If AB = 100 m, find height.
A50√2 m
B50 m
C100 m
D25√10 m
✓ Correct Answer: A — 50√2 m
x = h cot 30 = h√3. y = h cot 45 = h. x² + y² = 100². 3h² + h² = 10000. 4h² = 10000. h = 50 m. No, 50.
Share this question
More from Trigonometry
- Simplify the expression: (1 - cos 2A) / sin 2A.
- A vertical tower is surmounted by a flagstaff of height h. At a point on ground, elevations of bottom and top of flagstaff are α and β. Tower height is:
- The value of cot 45 is:
- If tan(A) = 1, then A is:
- If sin θ = p/q, then what is the value of sqrt(q² - p²) / p?