Trigonometryhard · Past Paper
From the top of a 60 m high building, the angles of depression of the top and bottom of a tower are observed to be 30° and 60°. The height of the tower is:
A40 m
B30 m
C20 m
D50 m
✓ Correct Answer: A — 40 m
Distance d = 60/tan 60 = 20√3. Height difference x = 20√3 * tan 30 = 20. Tower height = 60 - 20 = 40 m.
Share this question
More from Trigonometry
- Which of the following is equal to tan theta?
- Simplify: (1 - sin²θ) * sec²θ
- If the height of a pole is increased by 10%, and the angle of elevation remains 45°, the shadow length:
- If 2 cos theta = 1, find the value of theta.
- The angle of elevation of the top of a tower from two points at distances 'a' and 'b' (a > b) from the base and in the same straight line with it are complementary. The height of the tower is: