Trigonometryhard · Past Paper
Angle of elevation of an object from a point 100 m high is 30°. If the object is 200 m from the base, find its height.
A100(1 - 2/√3) m
B100 - 200/√3 m
C100 + 200/√3 m
D50 m
✓ Correct Answer: B — 100 - 200/√3 m
h_obj - 100 = 200 * tan 30. h_obj = 100 + 200/√3. Wait, if elevation is 30 from a point 100m high, then tan 30 = (H-100)/200. H = 100 + 200/√3.
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