Trigonometrymedium · Past Paper
An observer 1.5 m tall is 20.5 m away from a tower 22 m high. What is the angle of elevation?
A30°
B45°
C60°
D0°
✓ Correct Answer: B — 45°
Height difference = 22 - 1.5 = 20.5. Distance = 20.5. tan θ = 20.5/20.5 = 1. θ = 45°.
Share this question
More from Trigonometry
- Which trigonometric ratio is most commonly used in height and distance problems?
- A ladder rests against a wall at α to the horizontal. Its foot is pulled a distance 'a' away so it slides 'b' down the wall, making angle β. Find a/b.
- If tan A = 1/2 and tan B = 1/3, what is the value of tan(A + B)?
- Two poles 12 m and 18 m high stand vertically. If the string connecting their tops makes 30° with horizontal, find distance between them.
- What is the value of 1 - 2 sin² 22.5°?