Trigonometryeasy · Past Paper
A man 1.5 m tall is 28.5 m away from a tower 30 m high. What is the angle of elevation of the top of the tower from his eye?
A30°
B60°
C45°
D15°
✓ Correct Answer: C — 45°
Relative height = 30 - 1.5 = 28.5 m. Distance = 28.5 m. tan θ = 28.5 / 28.5 = 1, so θ = 45°.
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