Statisticshard · Past Paper
A bag contains 6 white and 4 black balls. If two balls are drawn with replacement, what is the probability that they are of different colors?
A0.48
B24/100
C0.50
D0.24
✓ Correct Answer: A — 0.48
P(WB) + P(BW) = (6/10 * 4/10) + (4/10 * 6/10) = 24/100 + 24/100 = 48/100 = 0.48.
Share this question