Geometryhard · Past Paper
The length of the angle bisector of angle A in triangle ABC is given by:
A(2bc cos A/2) / (b+c)
Bbc sin A
Csqrt(s(s-a))
D0.5 * a * h
✓ Correct Answer: A — (2bc cos A/2) / (b+c)
This formula provides the exact length of the internal angle bisector from vertex A.
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