Geometryhard · Past Paper
In an obtuse triangle ABC, where angle B > 90, the relation between sides is:
Ab^2 = a^2 + c^2
Bb^2 < a^2 + c^2
Cb^2 > a^2 + c^2
Db = a + c
✓ Correct Answer: C — b^2 > a^2 + c^2
For an obtuse triangle, the square of the side opposite the obtuse angle is greater than the sum of the squares of the other two sides.
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