Geometryhard · Past Paper
What is the distance between the points (sinθ, cosθ) and (cosθ, -sinθ)?
A1
Bsqrt(2)
C2
D0
✓ Correct Answer: B — sqrt(2)
d^2 = (cosθ-sinθ)^2 + (-sinθ-cosθ)^2 = cos^2 + sin^2 - 2sc + sin^2 + cos^2 + 2sc = 1 + 1 = 2. Distance = sqrt(2).
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