Geometrymedium · Past Paper
What is the area of a circle whose equation is x^2 + y^2 - 4x - 6y - 3 = 0?
A16 pi
B4 pi
C25 pi
D9 pi
✓ Correct Answer: A — 16 pi
g=-2, f=-3, c=-3. Radius r = sqrt(g^2+f^2-c) = sqrt(4+9+3) = 4. Area = pi * r^2 = 16 pi.
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