Geometrymedium · Past Paper
The center of the circle x^2 + y^2 - 4x + 6y - 12 = 0 is:
A(2, -3)
B(-2, 3)
C(4, -6)
D(2, 3)
✓ Correct Answer: A — (2, -3)
Center (h, k) = (-g, -f) where 2g = -4 and 2f = 6. Thus, h = 2, k = -3.
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