Geometryeasy · Past Paper
The area of a triangle with vertices (a, 0), (0, b), and (0, 0) is:
Aab
B1/2 ab
C1/2 (a+b)
Dsqrt(a^2+b^2)
✓ Correct Answer: B — 1/2 ab
It is a right-angled triangle with base 'a' and height 'b'. Area = 1/2 * a * b.
Share this question
More from Geometry
- If the lines 2x + ky + 3 = 0 and 4x + 6y + 9 = 0 are parallel, then k is:
- The centroid of a triangle divides each median in the ratio:
- If a circle is circumscribed about a right-angled triangle with legs 6 cm and 8 cm, find its radius.
- What is the reflex angle of 60 degrees?
- The area of a circle increases by what percent if its radius is doubled?