Geometryhard · Past Paper

If the line y = mx + c is a tangent to the circle x^2 + y^2 = a^2, then the condition is:

Ac^2 = a^2(1 + m^2)
Bc^2 = a^2 / (1 + m^2)
Cc = am
Dc^2 = a^2(1 - m^2)

✓ Correct Answer: Ac^2 = a^2(1 + m^2)

The perpendicular distance from origin (0,0) to mx - y + c = 0 must equal radius 'a'. |c|/sqrt(m^2+1) = a => c^2 = a^2(1+m^2).

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