Geometrymedium · Past Paper
Find the equation of a line passing through (1, -1) and perpendicular to the line x + 2y = 3.
Ax - 2y - 3 = 0
B2x - y - 3 = 0
C2x + y - 1 = 0
Dx + 2y + 1 = 0
✓ Correct Answer: B — 2x - y - 3 = 0
Perpendicular line: 2x - y + k = 0. Pass through (1, -1): 2(1) - (-1) + k = 0 => 2 + 1 + k = 0 => k = -3.
Share this question
More from Geometry
- Find the area of a triangle with vertices (1, 2), (3, 4), and (10, 6).
- If the sum of the radii of two circles which touch each other externally is 10 cm and the distance between their centers is 10 cm, how many common tangents do they have?
- The center of the circle x^2 + y^2 - 4x + 6y - 12 = 0 is:
- A triangle having all three sides equal is called:
- The point (0, -4) lies on which axis?