Geometryhard · Past Paper

Distance between (cos theta, sin theta) and (sin theta, -cos theta) is:

A1
Bsqrt(2)
C2
D0

✓ Correct Answer: Bsqrt(2)

D^2 = (sin - cos)^2 + (-cos - sin)^2 = sin^2 - 2sincos + cos^2 + cos^2 + 2sincos + sin^2 = 2(sin^2 + cos^2) = 2. So D = sqrt(2).

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