Geometrymedium · Past Paper
Two chords AB and CD of a circle intersect at E. If AE = 4 cm, EB = 6 cm, and CE = 3 cm, find the length of ED.
A4 cm
B5 cm
C8 cm
D12 cm
✓ Correct Answer: C — 8 cm
By the chord-chord power theorem, AE * EB = CE * ED. So, 4 * 6 = 3 * ED, which means 24 = 3 * ED, so ED = 8 cm.
Share this question
More from Geometry
- A wire in the form of a circle of radius 42 cm is cut and bent into a square. Find the side of the square.
- What is the angle between the hands of a clock at 8:30?
- The sum of the altitudes of a triangle is _____ its perimeter.
- What is the sum of opposite angles in a cyclic quadrilateral?
- What is the equation of the locus of a point which is always 5 units away from (0, 0)?