Geometrymedium · Past Paper
Two chords AB and CD of a circle intersect at E. If AE = 4 cm, EB = 6 cm, and CE = 3 cm, find the length of ED.
A4 cm
B5 cm
C8 cm
D12 cm
✓ Correct Answer: C — 8 cm
By the chord-chord power theorem, AE * EB = CE * ED. So, 4 * 6 = 3 * ED, which means 24 = 3 * ED, so ED = 8 cm.
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