Geometryhard · Past Paper
Three circles of radius 1 cm touch each other externally. What is the area of the region enclosed between them?
Asqrt(3) - pi/2
Bsqrt(3) - pi
C2*sqrt(3) - pi
Dsqrt(3) - 3*pi/2
✓ Correct Answer: A — sqrt(3) - pi/2
Area = Area of equilateral triangle (side 2) - 3 * Area of sector (60 deg, r=1). Area = sqrt(3)/4 * 2^2 - 3 * (60/360 * pi * 1^2) = sqrt(3) - pi/2.
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