Geometryhard · Past Paper
In a cyclic quadrilateral ABCD, side AB is the diameter. If angle ADC = 130 degrees, find angle BAC.
A40 degrees
B50 degrees
C90 degrees
D130 degrees
✓ Correct Answer: A — 40 degrees
ABC = 180 - 130 = 50. Angle ACB = 90 (semi-circle). BAC = 180 - 90 - 50 = 40 degrees.
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