Geometrymedium · Past Paper
In a circle, two chords AB and CD intersect at E. If AE = 4, EB = 3, and CE = 2, find ED.
A4
B5
C6
D8
✓ Correct Answer: C — 6
Property of chords: AE * EB = CE * ED => 4 * 3 = 2 * ED => 12 = 2 * ED => ED = 6.
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