Geometrymedium · Past Paper
In a circle, two chords AB and CD intersect at E. If AE = 4, EB = 3, and CE = 2, find ED.
A4
B5
C6
D8
✓ Correct Answer: C — 6
Property of chords: AE * EB = CE * ED => 4 * 3 = 2 * ED => 12 = 2 * ED => ED = 6.
Share this question
More from Geometry
- What is the perimeter of a triangle with side lengths 5 cm, 7 cm, and 10 cm?
- Two angles are supplementary. If one is 110 degrees, find the other.
- In a circle with center O, the measure of central angle AOB is 80 degrees. If the area of sector AOB is 16*pi, what is the radius?
- If an angle is 275 degrees, what type of angle is it?
- The length of the common chord of two intersecting circles is 24 cm. If their radii are 13 cm and 15 cm, find the distance between their centers.