Geometryhard · Past Paper
Find the radius of a circle where a chord of length 10 cm subtends an angle of 90 degrees at the center.
A5 cm
B5*sqrt(2) cm
C10 cm
D10*sqrt(2) cm
✓ Correct Answer: B — 5*sqrt(2) cm
In an isosceles right triangle with hypotenuse 10, r^2 + r^2 = 10^2, 2r^2 = 100, r^2 = 50, r = 5*sqrt(2).
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