Algebraeasy · Past Paper

Which of the following equations has imaginary roots?

Ax^2 + 1 = 0
Bx^2 - 1 = 0
Cx^2 + x - 1 = 0
Dx^2 - x - 1 = 0

✓ Correct Answer: Ax^2 + 1 = 0

For x^2 + 1, D = 0^2 - 4(1)(1) = -4. Negative discriminant means imaginary roots.

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