Algebraeasy · Past Paper
What is the constant term in the equation (x-2)(x-3) = 0?
A-5
B6
C-6
D5
✓ Correct Answer: B — 6
Expanding (x-2)(x-3) gives x^2 - 5x + 6. The constant term is 6.
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✓ Correct Answer: B — 6
Expanding (x-2)(x-3) gives x^2 - 5x + 6. The constant term is 6.
Share this question