Algebrahard · Past Paper
The sum of the squares of two consecutive odd numbers is 290. Find the numbers.
A11, 13
B13, 15
C9, 11
D7, 9
✓ Correct Answer: A — 11, 13
x^2 + (x+2)^2 = 290 => 2x^2 + 4x - 286 = 0 => x^2 + 2x - 143 = 0 => (x+13)(x-11)=0. x=11.
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