Algebraeasy · Past Paper
The roots of the equation x^2 + px + q = 0 are real and equal if:
Ap^2 = 4q
Bp^2 = q
Cq^2 = 4p
Dp = 4q
✓ Correct Answer: A — p^2 = 4q
D = p^2 - 4(1)(q) = 0 => p^2 = 4q.
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✓ Correct Answer: A — p^2 = 4q
D = p^2 - 4(1)(q) = 0 => p^2 = 4q.
Share this question