Algebrahard · Past Paper
The roots of the equation 4^x - 3 ⋅ 2^{x+2} + 32 = 0 are:
A1, 2
B2, 3
C3, 4
D2, 4
✓ Correct Answer: B — 2, 3
Let 2^x = y. Then y^2 - 12y + 32 = 0 => (y-8)(y-4)=0. y=4 or y=8 => 2^x=2^2 or 2^x=2^3. x=2, 3.
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✓ Correct Answer: B — 2, 3
Let 2^x = y. Then y^2 - 12y + 32 = 0 => (y-8)(y-4)=0. y=4 or y=8 => 2^x=2^2 or 2^x=2^3. x=2, 3.
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